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**Competitive ****Electric Circuits MCQs – ****Techniques of Circuit Analysis MCQs ( Electric Circuits ) MCQs**

#### Latest Electric Circuits MCQs

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**Techniques of Circuit Analysis MCQs ( Electric Circuits ) MCQs – Electric Circuits MCQs**

The most occurred **mcqs of Techniques of Circuit Analysis MCQs ( Electric Circuits )** in past papers. **Past papers of Techniques of Circuit Analysis MCQs ( Electric Circuits )** Mcqs. **Past papers of** **Techniques of Circuit Analysis MCQs ( Electric Circuits )** Mcqs . Mcqs are the necessary part of any competitive / job related exams. The Mcqs having specific numbers in any written test. It is therefore everyone have to learn / remember the related **Techniques of Circuit Analysis MCQs ( Electric Circuits )** Mcqs. The Important series of **Techniques of Circuit Analysis MCQs ( Electric Circuits )** Mcqs are given below:

# The Node-Voltage Method and Dependent Sources and Some Special Cases

**1. Nodal analysis is mainly based on __________****a) KCL**

b) KVL

c) Wheatstone bridge principle

d) Faradayâ€™s electric laws**Answer: a****Explanation: Nodal analysis or Node-Voltage method is done by identifying the currents at the node and thereby forming equations.****2. If there are n nodes, then how many node-voltage equations are required?**

a) n

b) n+1**c) n-1**

d) 1**Answer: c****Explanation: If there are n nodes then n-1 nodal equations are required to describe the circuit.****3. Find VA and VB using Node-Voltage method in the given circuit.**

a) 2.5V, 3.6V**b) 2.87V, 3.25V**

c) 2.65V, 3.47V

d) 3.15V, 2.76V**Answer: b****Explanation: Node A: V _{A}/2 + (V_{A}-1)/2 + (V_{A}-V_{B})/1 =2**

**Node B: (V**

_{B}-2)/2 + (VB-V_{A})/1 =1**By solving the above equations required voltages are obtained.**

**4. A supernode is between _____________**

a) Essential node and reference node

b) Two reference nodes

**c) Two essential nodes**

d) Essential node and neutral path

**Answer: c**

**Explanation: A supernode is between two essential nodes.**

**5. Find V3 in the circuit given below.**

**a) 4.833V**

b) 2.616V

c) -4.833V

d) -2.616V

**Answer: a**

**Explanation: supernode: V**

_{3}-V_{2}Â = 5V**Node1: 166V**

_{1}-100V_{2}-66V_{3}Â =132**Node3: -166V**

_{1}+265V_{2}+99V_{3}Â =0**On solving the required voltage is obtained.**

**6. Find all the node voltages in the given circuit containing dependent sources.**

**a) 10V, 20V, 30V, 40V**

b) 15V, 25V, 32V, 45V

c) 10V, -20V, 30V, -40V

d) -15V, 25V, -35V, 45V

**Answer: a**

**Explanation: At supernode: V**

_{C}-V_{B}=5i_{X}**And ix = (V**

_{B}-V_{A})/5. On solving remaining nodes and forming equations, the required voltage values at nodes are obtained.**7. What is the voltage at 2nd terminal in the given circuit?**

a) 132.57V

**b) 137.25V**

c) 173.25V

d) 123.57V

**Answer: b**

**Explanation: Given voltage source 135V is in between essential node and reference node. So that implies V**

_{1}Â =135V. Using this, V_{2}Â can be calculated.**8. If there are 5 nodes then the no of nodal equations are ___________**

a) 5

b) 0

c) 1

**d) 4**

**Answer: d**

**Explanation: If there are n nodes then n-1 nodal equations are required to describe the circuit.**

**9. If there are (N-2+3) Node-Voltage equations then the number of nodes in the circuit are __________**

**a) N+2**

b) N+1

c) N

d) N-1

**Answer: a**

**Explanation: If there are n nodes then n-1 nodal equations are required to describe the circuit. So, given N-2+3 i.e. N+1 nodal equations and it implies N+2 nodes.**

**10. The reference node is also known as __________**

a) Essential node

b) Principle node

**c) Datum node**

d) Neutral node

**Answer: c**

**Explanation: The node taken for reference in the network is known as reference node or datum node.**

**11. If there are 9 nodes, then how many node-voltage equations are required?**

a) 9

b) 10

**c) 8**

d) 1

**Answer: c**

**Explanation: If there are n nodes then n-1 nodal equations are required to describe the circuit.**

**12. There are 13 branches in a complicated network and nearly 8 nodes. How many equations are required to solve the circuit in node-voltage method?**

**a) 7**

b) 13

c) 5

d) 6

**Answer: a**

**Explanation: Branches number is not required in this method. Only nodes number is required.**

# The Mesh-Current Method and Dependent Sources and Some Special Cases

**1. The loop which does not contain any other inner loop is known as _____________**

a) A node**b) A mesh**

c) A branch

d) A super mesh**Answer: b****Explanation: A mesh is defined as a loop which does not contain any other loop within it.****2. If there are 6 branches and 4 essential nodes, how many equations are required to describe a circuit in mesh-current method?****a) 3**

b) 6

c) 4

d) 2**Answer: a****Explanation: In Mesh-Current method, b-(n-1) equations are required to describe the circuit. b= the number of branches and n= the number of essential nodes.****3. Find the current flowing through 5â„¦ resistor in the given circuit.**

a) 0.57A

b) 0.64A**c) 0.78A**

d) 0.89A**Answer: c****Explanation: There are 3 meshes in the given circuit. Assuming currents I _{1}, I_{2}, I_{3}Â in the 3 meshes and by applying KVL, equations will be obtained which on solving gives the respective currents flowing in the circuits.**

**4. A Super Mesh analysis could be done when there is a common _____________ between any two loops.**

a) Voltage source

**b) Current source**

c) Resistor

d) Both voltage and current source

**Answer: b**

**Explanation: A Super Mesh analysis could be done when there is a common current source between any two loops.**

**5. Calculate the current flowing through 10â„¦ resistor in the circuit shown below.**

**a) Â±0.435A**

b) Â±0.985A

c) 1.217A

d) 2.782A

**Answer: a**

**Explanation: Loop2 and loop3 forms a supermesh.**

**Supermesh: I**

_{3}-I_{2}=4**Loop1: 11I**

_{1}-10I_{2}=2**KVL at Supermesh: -2I**

_{1}+3I_{2}+3I_{3}=0**Solving these gives the currents flowing in the circuit and current through 10â„¦ resistor is either I**

_{1}-I_{2}Â or I_{2}-I_{1}.**6. Find the power delivered by the voltage source in the network given below.**

a) 65Watts

b) 72Watts

**c) 63Watts**

d) 76Watts

**Answer: c**

**Explanation: 3 loops and a supermesh between loop1 and loop3. Using KVL currents are found out. I**

_{1}=9A, I_{2}=2.5A, I_{3}=2A. As voltage source is in 1st loop, Power delivered by voltage source=V*I_{1}.**7. The Mesh-Current method is applicable only for ___________**

a) Non-linear networks

b) Equivalent networks

c) Non-planar networks

**d) Planar networks**

**Answer: d**

**Explanation: The Mesh-Current method is applicable only for Planar networks. A network is said to be planar if there are no crossovers in it and it can be drawn freely on a plane surface.**

**8. Find the value of V**

_{X}Â in the circuit given below.**a) â€“0.8A**

b) +0.8A

c) -4.8A

d) +4.8A

**Answer: a**

**Explanation: Applying KVL, currents could be found out. I**

_{1}=0.4A, I_{2}=2.4A. V_{X}=-I_{1}R_{1}.**9. A Supermesh is formed between two loops which share a common voltage source.**

a) True

**b) False**

**Answer: b**

**Explanation: Meshes that share a current source with other meshes, none of which contains a current source in the outer loop, forms a supermesh.**

**10. If 4 equations are required to describe a circuit by Mesh-Current method and there are n nodes. How many branches are there in the network?**

a) n+5

**b) n+3**

c) n

d) n-1

**Answer: b**

**Explanation: Standard formulae: b-(n-1)**

**Given b-(n-1) =4 -> b=4+ (n-1) =n+3.**

**11. If there are 16 branches and 5 essential nodes, how many equations are required to describe a circuit in mesh-current method?**

**a) 12**

b) 16

c) 21

d) 9

**Answer: a**

**Explanation: In Mesh-Current method, b-(n-1) equations are required to describe the circuit. b=the number of branches and n= the number of essential nodes.**

**12. Determine the current through 3â„¦ resistor in the network given below.**

a) 2A

b) 3A

**c) 4A**

d) -2A

**Answer: c**

**Explanation: Mesh1 and Mesh2 form a super mesh. Assuming currents I**

_{1}Â and I_{2}Â and applying KVL, the current through required resistor is found out.**13. Mesh analysis is best suitable for _____________**

**a) Current sources**

b) Voltage sources

c) Complex elements

d) Unilateral elements

**Answer: a**

**Explanation: Mesh analysis is best suitable for Current sources.**

# The Node-Voltage Method Versus the Mesh-Current Method

**1. Which method is best for voltage sources?**

a) Mesh analysis**b) Nodal analysis**

c) Superposition principle

d) Differentiation method**Answer: b****Explanation: Every voltage source connected to the reference node reduces the equations to be solved. Thus, the node-voltage method is best for voltage sources.****2. When there is a current source between two loops which method is preferred?**

a) Mesh-voltage analysis

b) Node-current analysis**c) Supermesh**

d) Supernode**Answer: c****Explanation: Supermesh is taken into consideration when there is a current source n between two loops and is considered as one single loop.****3. Determine the current through 5â„¦ resistor in the network given below.****a) 3.38A**

b) 6.01A

c) 3.27A

d) 1.27A**Answer: a****Explanation: This problem can be solved quickly by using the mesh-current method. 3loops=3 KVL equations. Solving them gives respective currents.****4. Find the power supplied by the dependent voltage source in the circuit given below.**

a) 400W**b) 383W**

c) 412W

d) 148W**Answer: b****Explanation: 3loops=3KVL equations. Solving them gives currents flowing in the circuit. I _{1}=5A, I_{2}=-1.47A, I_{3}=0.56A .Power supplied by dependent voltage source =0.4V_{1}Â (I_{1}-I_{2}).**

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Inductance, Capacitance And Mutual Inductance MCQs

**5. Determine the voltage V _{2}Â of the network given.**

**a) 0V**

b) 1V

c) 4/7V

d) -4/7V

**Answer: a**

**Explanation: As there are voltage sources and nodes, node-voltage method is best suitable. Solving gives V**

_{1}Â =4/7V and V_{2}=0 (since there is no voltage source near node2).**6. If there are b branches and n nodes, then how many node-voltage equations are required?**

a) n

b) b+1

**c) n-1**

d) b

**Answer: c**

**Explanation: If there are n nodes then n-1 nodal equations are required to describe the circuit. Branches do nothing in this case.**

**7. There are 6 branches and 2 essential nodes then 3 equations are required to describe a circuit in the mesh-current method.**

a) True

**b) False**

**Answer: b**

**Explanation: In Mesh-Current method, b-(n-1) equations are required to describe the circuit. b= the number of branches and n= the number of essential nodes. So, 6-(2-1) =5.**

**8. Determine V**

_{1}Â of the given network.a) -0.17V

b) 4.83V

c) 5V

**d) 2.62V**

**Answer: d**

**Explanation: Supernode: V**

_{3}-V_{2}=5. Applying KCL at node1 and at supernode gives the equations which on solving, required voltages are obtained.**9. When there is a voltage source between two nodes which method is preferred?**

a) Mesh-voltage analysis

b) Node-current analysis

c) Supermesh

**d) Supernode**

**Answer: d**

**Explanation: Supernode is taken into consideration when there is a voltage source n between two nodes.**

**10. Which is the best-preferred method to calculate currents flowing in the circuit?**

**a) Mesh-voltage analysis**

b) Node-current analysis

c) Superposition principle

d) Duality principle

**Answer: a**

**Explanation: By KVL, currents can be easily found out in mesh-voltage method.**

# Source Transformations

**1. By using source transformation voltage source in series resistor is replaced by __________**

a) Voltage source in series with a resistor**b) Current source in parallel with a resistor**

c) Voltage source in parallel with a resistor

d) Current source in series with a resistor**Answer: b****Explanation: In Source transformation, a voltage source in series with a resistor is replaced by a current source in parallel with the same resistor and vice versa.****2. Source Transformation is _____________**

a) Unilateral

b) Unique**c) Bilateral**

d) Complicated**Answer: c****Explanation: In Source transformation, a voltage source in series with a resistor is replaced by a current source in parallel with the same resistor and vice versa. So, it is bilateral.****3. If there are two resistors in parallel and in series with a voltage source then ___________****a) Parallel resistor has no effect**

b) Series resistor has no effect

c) Both has their respective effects

d) Both has no effect on the voltage source**Answer: a****Explanation: In source transformation, the voltage source in series with a resistor to be replaced by a current source in parallel with the same resistor and vice versa. So other resistors are redundant and have no effect.****4. Using source transformation, calculate the voltage.**

a) 4.33V**b) 39V**

c) 0.230V

d) 36V**Answer: b****Explanation: V=IR=13*3=39V.****5. Which element(s) has no effect in the given circuit?**

a) 7â„¦**b) 10â„¦**

c) Both 7â„¦ and 10â„¦

d) Voltage source.**Answer: b****Explanation: Voltage in series with a resistor in replaced by a current source but here 10â„¦ is in parallel. So, it is redundant and has no effect.****6. The value of current source is __________ after replacing the given network with a single current source and a resistor.**

a) 70V

b) 60V

c) 90V**d) 80V****Answer: d****Explanation: In the given circuit 9â„¦ resistor has no effect.****10*6=60V, 60V+20V=80V.****7. If there is a 12A current source in series with 2â„¦ and in parallel with a 4â„¦ resistor, then voltage V=?**

a) 24V**b) 48V**

c) 3V

d) 6V**Answer: b****Explanation: 2â„¦ resistor is redundant. 12*4=48V.****8. Find the current flowing through 4â„¦ resistor shown in network below.**

a) 1.33A

b) 2.35A**c) 1.66A**

d) 2.66A**Answer: c****Explanation: By using source transformation the above network is reduced and then by current division rule I _{4â„¦}= 5*(2/2+4) =1.66A.**

**9. Calculate the power delivered by the 50V source.**

**a) 274W**

b) 276W

c) 285W

d) 291W

**Answer: a**

**Explanation: By using source transformation the above network is reduced and current in the circuit is found out and later power delivered by 50V source= 50*current in the circuit= 50*5.48A= 274W.**

**10. Source transformation can be used for dependent sources.**

**a) True**

b) False

**Answer: a**

**Explanation: Source transformation can be used for dependent sources. However, the controlling variable must not be tampered with any way since the controlled source operation depends on it.**

**11. Using source transformation, calculate vm.**

a) 2v

**b) -2v**

c) 1v

d) -1v

**Answer: b**

**Explanation: Using source transformation, the network is reduced and at last voltage is obtained.**

**12. Find the voltage value Vm in the circuit given below.**

**a) -3V**

b) 3V

c) 2.1V

d) -2.1V

**Answer: a**

**Explanation: Using source transformation, the voltage source in series with a resistor to be replaced by a current source in parallel with the same resistor and vice versa.**

**13. Source transformation technique is mainly based on __________ law.**

a) Newtonâ€™s

b) Kirchhoffâ€™s

**c) Ohmâ€™s**

d) Einsteinâ€™s

**Answer: c**

**Explanation: Ohmâ€™s law: V=iR. By using this, the voltage/ current sources are reduced.**

**14. In source transformation,**

a) Voltage sources remain same

b) Current sources remain same

c) Both voltage and current sources undergo change

**d) Resistances/Impedances remain same**

**Answer: d**

**Explanation: In source transformation, only the particular voltage/current sources change whereas the resistances remain same.**

**15. If there are five 20V voltage sources in parallel, then in source transformation __________**

a) All are considered

**b) Only one is considered**

c) All are ignored

d) Only 2 are considered

**Answer: b**

**Explanation: In parallel, voltages are same. So, only is considered and rest are ignored.**

# Thevenin and Norton Equivalents, More on Deriving a Thevenin Equivalent

**1. Find the voltage across 24â„¦ resistor by using Theveninâ€™s theorem.****a) 8V**

b) 9V

c) 1V

d) 6V**Answer: a****Explanation: 1. Remove 24â„¦ resistor and calculate the voltage across the open circuit.****2. Calculate the theveninâ€™s resistance and by using it, the theveninâ€™s current.****3. V _{24â„¦}=I*R (can also verify by using Nodal analysis).**

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**2. Calculate Theveninâ€™s voltage for the network shown below where the voltage source is 4V.**

a) 6V

b) 4.71V**c) 5V**

d) 1V**Answer: c****Explanation: In the circuit given, theveninâ€™s voltage is nothing but the open circuit voltage which is V _{x}. Applying KVL, it is obtained.**

**3. Find the Theveninâ€™s resistance for the network given.**

**a) 6.75â„¦**

b) 5.85â„¦

c) 4.79â„¦

d) 1.675â„¦

**Answer: a**

**Explanation: Remove all the voltage/current sources and calculate the equivalent resistance.**

**4. Find the current through (5+j4) â„¦ resistor.**

**a) 0.9-j0.2 A**

b) 0.78-j0.1 A

c) 2.7-j0.5 A

d) 1A

**Answer: a**

**Explanation: 1. Remove the 5+j4 â„¦ branch and calculate theveninâ€™s voltage.**

**(V= v across 6â„¦ resistor- v across 8â„¦ resistor)**

**2. Calculate Z**

_{th}. (10//6 and 8//8)**3. Current= (V**

_{th}/ (Z_{th}+Z).**5. The voltage across 6â„¦ resistor is __________**

a) 7.5V

b) 6.78V

c) 20V

**d) 8.5V**

**Answer: d**

**Explanation: Remove the resistor across which voltage is to be calculated and short circuit it. By using short circuit current and resistance calculate the current across 6â„¦ resistor and thereby voltage. (In this 10â„¦ resistor is also short-circuited since 10//0).**

**6. Find the Nortonâ€™s current for the circuit given below.**

a) 5A

b) 3.33A

**c) 4A**

d) 1.66A

**Answer: c**

**Explanation: I**

_{N}= (20/10) + (10/5).**7. Calculate IN for the given network.**

**a) 0A**

b) 1A

c) 4.37A

d) 0.37A

**Answer: a**

**Explanation: Using nodal analysis V**

_{x}Â is calculated. I_{N}Â =V_{x}/4.**8. Calculate R**

_{Th}Â for the network given.a) 8â„¦

**b) 7â„¦**

c) 2â„¦

d) 1â„¦

**Answer: b**

**Explanation: 5//20 and then in series with 3â„¦ resistor.**

**9. Theveninâ€™s equivalent circuit consists of a ____________**

**a) Voltage source in series with a resistor**

b) Current source in parallel with a resistor

c) Voltage source in parallel with a resistor

d) Current source in series with a resistor

**Answer: a**

**Explanation: Theveninâ€™s equivalent circuit contains a Voltage source in series with a resistor.**

**10. Nortonâ€™s equivalent circuit consists of a _____________**

a) Voltage source in series with a resistor

**b) Current source in parallel with a resistor**

c) Both voltage and current sources

d) Current source in series with a resistor

**Answer: b**

**Explanation: Nortonâ€™s equivalent circuit consists of a Current source in parallel with a resistor.**

**11. Theveninâ€™s voltage is equal to ____________**

a) Short circuit voltage

b) Open circuit current

**c) Open circuit voltage**

d) Short circuit current

**Answer: c**

**Explanation: Theveninâ€™s voltage is equal to open circuit voltage.**

**12. Nortonâ€™s current is equal to ____________**

a) Short circuit voltage

b) Open circuit current

c) Open circuit voltage

**d) Short circuit current**

**Answer: d**

**Explanation: Nortonâ€™s current is equal to Short circuit current.**

**13. Theveninâ€™s resistance R**

_{Th}Â = ___________**a) V**

_{Th}/I_{SC}b) VSC/I

_{Th}

c) V

_{Th}/I

_{Th}

d) V

_{SC}Â /I

_{SC}

**Answer: a**

**Explanation: Theveninâ€™s resistance is defined as the ratio of open circuit voltage to the short circuit current across the terminals of the original circuit.**

**14. What is the expression forthe theveninâ€™s current if there is an external resistance in series with the R**

_{Th}?a) V

_{Th}/I

_{Th}

b) V

_{Th}/ (R

_{Th}-R)

**c) V**

_{Th}/ (R_{Th}+R)d) V

_{Th}/R

_{Th}

**Answer: c**

**Explanation: I**

_{Th}= V_{Th}/ (R_{Th}+R).**15. One can find the theveninâ€™s resistance simply by removing all voltage/current sources and calculating equivalent resistance.**

a) False

**b) True**

**Answer: b**

**Explanation: Yes. One can find the theveninâ€™s resistance simply by removing all voltage/current sources and calculating equivalent resistance.**

# Maximum Power Transfer and Superposition

**1. Which of the following is the example to describe the efficiency of power transfer?**

a) Communication systems**b) Power utility systems**

c) Instrumentation systems

d) Telecom systems**Answer: b****Explanation: Power utility systems are good examples for this case as they are concerned with the generation, transmission and distribution of power in large quantities.****2. In a network maximum power transfer occurs when __________**

a) R_{Th}= -R_{L}

b) R_{Th}/R_{L}Â =0**c) R _{Th}= R_{L}**

d) R

_{Th}+R

_{L}= 1

**Answer: c**

**Explanation: Maximum power transfer occurs when load resistance equals the theveninâ€™s resistance.**

**3. Maximum power in terms of the theveninâ€™s voltage and load resistance __________**

**a) (V**

_{Th}) 2 /4R_{L}b) (V

_{Th}) 2 *4R

_{L}

c) (V

_{Th}) 2 +4R

_{L}

d) 4R

_{L}/ (V

_{Th}) 2

**Answer: a**

**Explanation: P**

_{max}= v*i= i*R*i= i2R_{L}Â = (V_{Th}/(R_{Th}+R_{L}))2*R_{L}. Max power occurs when R_{L}=R_{Th}.**4. Calculate the maximum power delivered across R**

_{L}Â of the circuit given.a) 900W

b) 1025W

**c) 2025W**

d) 1500W

**Answer: c**

**Explanation: Pmax= (V**

_{Th}/(R_{Th}+R_{L}))^{2}*R_{L}Â (R_{Th}=R_{L})**V**

_{Th}= (150/150+30)*540= 450V**R**

_{Th}=(150*30)/180= 25â„¦ (the given resistors are in parallel).**5. Determine the maximum power delivered to the load in the network given.**

**a) 4.68W**

b) 5.75W

c) 3.16W

d) 6.84W

**Answer: a**

**Explanation: Load is given across node V**

_{2}Â and reference path. It implies the theveninâ€™s voltage is V_{2}. By using nodal analysis this voltage is found out.**R**

_{Th}=RL= 10â„¦//5â„¦ and in series with 2â„¦ and then parallel with 3â„¦=1.92â„¦**Max power = (V**

_{Th})^{Â 2}Â /4R_{L}Â = 4.688W.**6. The Superposition principle is obeyed by ____________**

**a) Linear networks**

b) Non-linear networks

c) Lateral networks

d) Trilateral networks

**Answer: a**

**Explanation: A linear system obeys Superposition Principle. In a linear network parameters are constant i/e/ wonâ€™t change with voltage and current.**

**7. According to Superposition principle response in one element is the algebraic sum of responses by individual sources acting alone.**

a) False

**b) True**

**Answer: b**

**Explanation: According to Superposition principle response in one element is the algebraic sum of responses by individual sources acting alone while other sources are non-operative.**

**8. Find the current in the 3â„¦ resistor of the given network using Superposition principle.**

a) 2.5A

b) 3.125A

c) 6.525A

**d) 5.625A**

**Answer: d**

**Explanation: 1.When 20v source acting alone: current source is replaced by open circuit. R**

_{eq}= 5+3=8â„¦ and Current I= 20/8=2.5A**2. When 5A source acting alone: 20v source is replaced by a short circuit. By current division rule, I**

_{3}= 25/8=3.125A**Total current through I**

_{3}= 2.5+3.125=5.625A.**9. Find the current in 5â„¦ resistor near 12V source using superposition principle in network given**

a) 2.9A

**b) -2.9A**

c) 1A

d) -1A

**Answer: b**

**Explanation: Only 3 sources are considered (12V, 10A, 20V), other is dependent (10I).**

**12v source: I=0.6A**

**10A source: I=-2.5A through 5â„¦ resistor and I=7.5A**

**20v source: I=-1A**

**Total current = 0.6+ (-2.5) + (-1) = -2.9A.**

**10. If there are 5 sources in a network out of which 3 are dependent and 2 are independent. For superposition principle ___________ sources are considered.**

a) 5

b) 3

**c) 2**

d) 0

**Answer: c**

**Explanation: Only independent sources are considered while using Superposition principle. Dependent sources are never deactivated while using this principle.**

**11. Find the current in the 1â„¦ resistor of the given circuit.**

**a) 4A**

b) 1.33A

c) 2A

d) 0.66A

**Answer: a**

**Explanation: when all the sources are acting alone the corresponding currents are found out using current division rule and finally all are summated to get the required current through the1â„¦ resistor. (Current = 1.33+0.66+2=4A).**

**12. Find the value of RL in given circuit.**

a) 4â„¦

b) 5â„¦

**c) 3â„¦**

d) 1.66â„¦

**Answer: c**

**Explanation: R**

_{Th}=R_{L}= (2//2) + 2=3â„¦.**13. Calculate the maximum power delivered to load in the network given.**

**a) 1.56W**

b) 1.66W

c) 2.33W

d) 2.79W

**Answer: a**

**Explanation: 1.Calculation of V**

_{Th}. (by using mesh analysis)**2. Calculation of Nortonâ€™s current.**

**3. Calculation of R**

_{Th}. (R_{Th}=V_{Th}/I_{N})**4. R**

_{Th}=R_{L}Â and P_{Max}= V_{Th}/4R_{L}.**14. In AC networks, maximum power is delivered when __________**

a) Z

_{L}*Z

_{S}*=0

b) Z

_{L}+Z

_{S}*=1

c) Z

_{L}=-Z

_{S}*

**d) Z**

_{L}=Z_{S}***Answer: d**

**Explanation: Max power is delivered when load impedance equals complex conjugate of the source impedance.**

**15. Superposition principle states that at a time __________ source(S) acts.**

a) All the given sources

b) Only voltage sources

**c) Only one source**

d) Only current sources

**Answer: c**

**Explanation: Only one source acts at a time. Remaining sources are non-operative during this period.**

**Competitive ****Electric Circuits MCQs – ****Techniques of Circuit Analysis MCQs ( Electric Circuits ) MCQs**

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