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**Up To Date ****Electric Circuits MCQs – ****Simple Resistive Circuits MCQs ( Electric Circuits ) MCQs**

#### Latest Electric Circuits MCQs

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**Simple Resistive Circuits MCQs ( Electric Circuits ) MCQs – Electric Circuits MCQs**

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# The Voltage Divider and Current Divider Circuits

**1. Where voltage division problem arises****a) Series connected resistors**

b) Parallel connected resistors

c) When resistors are equal

d) Both series and parallel resistors.**Answer: a****Explanation: In series, voltage is the difference and current same.****2. Where current division problem arises**

a) Series connected resistors**b) Parallel connected resistors**

c) When resistors are equal

d) Both series and parallel resistors.**Answer: b****Explanation: In parallel voltage is same and current is the difference.****3. If there are 3 Resistors R _{1}, R_{2} and R_{3} in series and V is total voltage and I is total current then Voltage across R_{2} is**

a) V R

_{3}/ R

_{1}+ R

_{2}+ R

_{3}

**b) V R**

_{2}/ R_{1}+ R_{2}+ R_{3}c) V R

_{1}/R

_{1}+ R

_{2}+ R

_{3}

d) V

**Answer: b**

**Explanation: V**

_{2}=I R_{2}**= V R**

_{2}/ R_{1}+ R_{2}+ R_{3}.4.

**Calculate Voltage across 2Ω Resistor where supply v= 10volts.**

a) 2V

b) 3V

c) 10V

**d) 4V**

**Answer: d**

**Explanation: I = 10/5 = 2A**

**V**

_{2}= 10(2)**V**

_{2}= I.R_{2}**= 2(2)**

**4V.**

5.

**Calculate i =?**

a) -1A

**b) +2A**

c) 8A

d) -5A

**Answer: b**

**Explanation: i = 1/1+3(8)**

**= 2A.**

**6. For a parallel connected resistor R**

_{1}, R_{2}and a voltage of V volts. Current across the first resistor is given bya) I R

_{1}

b) I R

_{2}

c) I R

_{1}/ R

_{1}+ R

_{2}

**d) I R**

_{2}/ R_{1}+ R_{2}**Answer: d**

**Explanation: I**

_{1}= V / R_{1}**R = R**

_{1}. R_{2}/ R_{1}+ R_{2}**= I . R**

_{1}. R_{2}/ R_{1}. R_{1}+ R_{2}**I**

_{1}= I R_{2}/ R_{1}+ R_{2}.**7. R**

_{1}= 1Ω, R_{2}= 3Ω, R_{3}= 5Ω and R_{4}= 7Ω connected in series. Total voltage = 20V, Current I, V2 =?a) I = 1.23, V

_{2}= 3.75

**b) I = 1.25, V**

_{2}= 3.75c) I = 1.15, V

_{2}= 3.73

d) I = 1.16, V

_{2}= 3.72

**Answer: b**

**Explanation: I = 20/ 1 + 3 + 5 + 7 = 1.25A**

**V**

_{2}= V. R_{2}/ R_{1}+ R_{2}+ R_{3}+ R_{4}**= 20(3)/16**

**= 3.75V.**

**8. R**

_{1}= 1Ω, R_{2}= 3Ω, R_{3}= 5Ω and R_{4}= 7Ω connected in parallel. Total Current = 23A. Then V, I_{1}, I_{2}=?**a) 12.26v, 1.725, 2.875**

b) 12.23v, 2.875, 1.725

c) 11.26v, 1.95, 1.74

d) 11.23v, 1.74, 1.95

**Answer: a**

**Explanation: V = I/R**

**V = I (R**

_{1}+ R_{2}) R_{1}R_{2}= 12.26v**I1 = IR**

_{2}/ R_{1}+ R_{2}= 1.725A**I**

_{2}= IR_{1}/ R_{1}+ R_{2}**= 2.875A.**

**9. Voltage division is necessary for parallel resistance networks**

a) True

**b) False**

**Answer: b**

**Explanation: In parallel, connection voltage is same so no division is required.**

**10. Why is current division necessary?**

a) In series current is the same

**b) In parallel current differs**

c) Because the voltage is also different

d) Because of Kirchhoff’s laws.

**Answer: b**

**Explanation: In parallel current differs.**

# Measuring Voltage and Current

**1. ____________ helps in current measurement by placing it in ____________ with the circuit element.**

a) Voltmeter, Parallel**b) Ammeter, series**

c) Voltmeter, series

d) Ammeter, parallel**Answer: b****Explanation: In series, current is same. So Ammeter is placed in series and is used to measure current.****2. An ideal voltmeter has ___________ equivalent resistance and ideal ammeter has ___________ equivalent resistance.**

a) Unity, Unity

b) Zero, infinite**c) Infinite, Zero**

d) Zero, Zero**Answer: c****Explanation: An ideal voltmeter has Infinite equivalent resistance and ideal ammeter has zero equivalent resistance.****3. Continuous voltages (or) current signals are measured using**

a) Tachometers

b) Sonometers

c) Analog meters**d) Digital meters****Answer: d****Explanation: Digital meters are used to measure current (or) voltage signals at discrete points in time known as sampling times.****4. Digital meters are preferable than analog meters.****a) True**

b) False**Answer: a****Explanation: Features like easy connection, Introduction of less resistance into the circuit to which they all connected and also due to read out mechanism digital meter are preferred.****5. A 20mv, 1mA d’Arsonval movement is used in an ammeter whose full-scale reading is 10 mA. Determine R _{A}.**

**a) 2.222Ω**

b) 6.667Ω

c) 5.92Ω

d) 3.333Ω

**Answer: a**

**Explanation:**

**1 mA flowing through coil implies that 9mA must be diverted through RA.**

**V = ir**

**20 * 10**

^{-3 }= 9 * 10^{-3}R_{A}**R**

_{A}= 2.222Ω.**6. A 25mv, 2mA d’Arsonval movement is to be used in voltmeter whose full scale reading is 100v. The resistance inserted by 100v meter into circuit is ___________**

**a) 1 * 10**

^{5}Ωb) 1 * 10

^{6}Ω

c) 1 * 10

^{4}Ω

d) 1 * 10

^{3}Ω

**Answer: a**

**Explanation: v = iR**

**R = v/i**

**= 100/1mA**

**= 100,000Ω.**

Circuit Variables And Elements MCQs

**7. An ideal voltmeter functions as __________ circuit**

a) A short**b) An open**

c) A power

d) An infinite**Answer: b****Explanation: An ideal voltmeter offers an infinite equivalent resistance. So acts as an open circuit.****8. An ideal ammeter functions as __________ circuit****a) A short**

b) An open

c) A power

d) An infinite**Answer: a****Explanation: An ideal ammeter offers a zero equivalent resistance. So acts a short circuit.****9. A 100mv, 5mA d’Arsonval movement is to be used in an ammeter whose full-scale reading is 1A. Calculate RA.**

a) 0.7 ohms

b) 0.5 ohms**c) 0.1 ohms**

d) 0.2 ohms**Answer: c****Explanation: 5mA is flowing through the coil which implies 995mA are diverted through R _{A}.**

**V = iR**

**= 100 * 10**

^{-3}**= 995 * 10**

^{-3}R_{A}**RA = 0.100Ω.**

**10. A 122mv, 12mA d’Arsonval movement is to be used in voltmeter whose full scale reading is 120v. The resistance inserted by 120v _____________**

a) 1200Ω

b) 12000Ω

c) 1000Ω

**d) 10,000Ω**

**Answer: d**

**Explanation: R =120/12 * 10**

^{-3}**= 10,000Ω.**

# Measuring Resistance the Wheatstone Bridge and Delta-to-Wye (Pi-to-Tee) Equivalent Circuits

**1. The Wheatstone Bridge is mainly used to measure ______________**

a) Currents

b) Voltages

c) Node potentials**d) Resistances****Answer: d****Explanation: Resistances can be measured by various methods. Wheatstone bridge is one such method. In this method resistances in the range of 1Ω to 1 MΩ can be measured.****2. The relation between the resistances in the given Wheatstone bridge circuit is _____________**

a) P/S = R/Q

b) PR = QS**c) P/Q = R/S**

d) PQ = RS**Answer: c****Explanation: The relation is P/Q=R/S or PS=QR.****3. Find the unknown resistance value in given circuit.****a) 10.2Ω**

b) 11.7Ω

c) 10.5Ω

d) 11.5Ω**Answer: a****Explanation: A/B=C/D. Using this D= 10.2Ω.****4. Lower resistances are difficult to measure using Wheatstone bridge circuit because of ____________**

a) Leakage currents**b) I ^{2}R effects**

c) Power dissipation

d) Thermal breakdown

**Answer: b**

**Explanation: A standard Wheatstone bridge couldn’t measure lower resistances because of thermoelectric voltages which are generated at the junctions of the dissimilar metals and also because of thermal heating effects- that is, i**

^{2}R effects.**5. If P/Q=1, unknown resistance S=1000Ω and R could be varied from 0 to 100Ω then the bridge could be ___________**

a) A balanced circuit

b) A rectified circuit

**c) An unbalanced circuit**

d) An identical circuit

**Answer: c**

**Explanation: P/Q=R/S. If P/Q=1 then according to given range of R and S, the bridge circuit could never be a balanced one.**

**6. The other name for Delta connection is ___________**

a) Star connection

**b) Pi connection**

c) T connection

d) Y connection

**Answer: b**

**Explanation: Delta connection is also known as Pi connection because the ∆ can be shaped into π without disturbing the electrical equivalence of both the structures.**

**7. Star connection can also be called as Y (or) T connection.**

**a) True**

b) False

**Answer: a**

**Explanation: Star connection can also be called as Y (or) T connection because the star can be shaped into Y or T without disturbing the electrical equivalence of both the structures.**

**8. If R**

_{2}= R_{C}R_{A}/ (R_{A}+R_{B}+R_{C}) then R_{3}equals?**a) R**

_{A}R_{B}/ (R_{A}+R_{B}+R_{C})b) R

_{C}R

_{A}/ (R

_{A}+R

_{B}+R

_{C})

c) R

_{B}R

_{C}/ (R

_{A}+R

_{B}+R

_{C})

d) R

_{X}R

_{A}/ (R

_{A}+R

_{B}+R

_{C})

**Answer: a**

**Explanation: R**

_{3}= R_{A}R_{B}/ (R_{A}+R_{B}+R_{C}).**9. Convert the given Delta circuit to star circuit and give the R _{a} , R_{b} and R_{c} values.**

a) R_{a}=5Ω, R_{b} = 4.5Ω, R_{c}=4.67Ω**b) R _{a}=4Ω, R_{b}=4.30Ω, R_{c}=4.66Ω**

c) R

_{a}=3Ω, R

_{b}=4Ω, R

_{c}=5Ω

d) R

_{a}=5.2Ω, R

_{b}=4.2Ω, R

_{c}=4.89Ω

**Answer: b**

**Explanation: By using the standard formulae the delta circuit can be converted into star circuit.**

**10. Find V**

_{AB}if i_{AB}= 5A.a) 32.76V

b) 35.56V

c) 36.12V

**d) 34.21V**

**Answer: d**

**Explanation: By converting the star circuits into the delta and then measuring the equivalent resistance, voltage value can be calculated using this resistance and the given current value.**

**11. Convert the given star network into Pi network and calculate the sum of all the resistances in the obtained Pi network.**

a) 125.5Ω

**b) 122.5Ω**

c) 127.8Ω

d) 129.8Ω

**Answer: b**

**Explanation: Conversion of given network into delta gives the resistances.**

**After that sum of the resistances equals 122.5Ω.**

**12. The star and delta networks would be electrically equal if resistances measured between any pair of terminals __________**

a) Is different

b) Greater in star

c) Greater in delta

**d) Is equal**

**Answer: d**

**Explanation: The star and delta networks would be electrically equal if a resistance measured between any pair of terminals is same.**

**13. A Wheatstone bridge is balanced when the galvanometer shows __________ reading.**

**a) 0A**

b) 1A

c) Infinity

d) -1A

**Answer: a**

**Explanation: A Wheatstone bridge is balanced when the galvanometer shows 0A reading when resistors obey P/Q=R/S.**

**14. __________ are difficult to measure using Wheatstone bridge.**

a) Higher resistances

b) Currents

**c) Lower resistances**

d) Voltages

**Answer: c**

**Explanation: Specifically Kelvin Bridge is used for measuring lower resistances.**

**15. What will be the resistance between B and C when the network given below is converted into delta?**

a) 13Ω

**b) 8.66Ω**

c) 6.5Ω

d) 7.33Ω

**Answer: b**

**Explanation: Resistance between B and C = 2+4+ ((2*4)/3).**

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